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18x^2-96x+128=0
a = 18; b = -96; c = +128;
Δ = b2-4ac
Δ = -962-4·18·128
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{96}{36}=2+2/3$
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